-5x^2+0x+3=0

Solution for -5x^2+0x+3=0 equation:

-5x^2+0x+3=0

We add all the numbers together, and all the variables

-5x^2+x+3=0

a = -5; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·(-5)·3
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{61}}{2*-5}=\frac{-1-\sqrt{61}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{61}}{2*-5}=\frac{-1+\sqrt{61}}{-10}
$